document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1174920>Question 1174920</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The average of six number is 4. If the average of two numbers is 2 what is the average of the other four numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #800423 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13203)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=800423\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The other tutor showed a standard basic method for solving a problem like this involving averages, using the definition of average.<br><BR>\n" );
document.write( "Here is an alternative method that I find faster and easier when the numbers are all \"close together\".<br><BR>\n" );
document.write( "The average of six numbers is 4; the average of two of those numbers is 2.<BR>\n" );
document.write( "Each of those two numbers is 2 short of the overall average, so between them they are a total of 2*2=4 short of the average.<BR>\n" );
document.write( "That means the remaining numbers together must be 4 over the average.<BR>\n" );
document.write( "Since there are four other numbers, each of them must be over the average by 4/4=1.<BR>\n" );
document.write( "So the average of the other four numbers must be 4+1=5.<br><BR>\n" );
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