document.write( "Question 1174878: A bus travels between towns A and B. It travels half the distance between A and B at 40 mph, and the rest of the distance at 50 mph. On the return trip, the bus travels for the first 2 hours at 35 mph, and the rest of the time at 40 mph. What is the distance between A and B, if the trip from B to A is an hour longer than the trip from A to B? \n" ); document.write( "

Algebra.Com's Answer #800399 by MathTherapy(10552) $\"\"$ $\"About$

You can put this solution on YOUR website!

\n" ); document.write( "A bus travels between towns A and B. It travels half the distance between A and B at 40 mph, and the rest of the distance at 50 mph. On the return trip, the bus travels for the first 2 hours at 35 mph, and the rest of the time at 40 mph. What is the distance between A and B, if the trip from B to A is an hour longer than the trip from A to B?
\n" ); document.write( "

Let distance from A to B be D\r\n" );
document.write( "One-half distance from A to B: ½D, or \r\n" );
document.write( "Time taken to travel ½ distance, from A to B: \r\n" );
document.write( "Time taken to travel remainder of distance, from A to B: \r\n" );
document.write( "Time taken to travel from A to B: \r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "On return trip, it travels for 2 hours at 35 mph, for a distance of 2(35) = 70 miles\r\n" );
document.write( "Therefore, remaining journey on 2nd leg = D - 70 \r\n" );
document.write( "If return trip takes 1 more hour that outbound, then time taken to complete return trip = \r\n" );
document.write( "With 1st leg of return trip taking 2 hours, 2nd leg takes \r\n" );
document.write( "\r\n" );
document.write( "At 40 mph, a time of , and distance of D - 70, we get: \r\n" );
document.write( "9D - 10D = - 300 ------- Multiplying by LCD, 10\r\n" );
document.write( "- D = - 300\r\n" );
document.write( "Distance from A to B, or

\n" ); document.write( "

\n" );