document.write( "Question 109840This question is from textbook beginning algebra
\n" ); document.write( ": Jill has 3.50$ in nickels and dimes. If she has 50 coins, how many of each type of coin does she have? \n" ); document.write( "
Algebra.Com's Answer #80031 by josmiceli(19441)\"\" \"About 
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n = number of nickels
\n" ); document.write( "d = number of dimes
\n" ); document.write( "\"n+%2B+d+=+50\" there are 50 coins
\n" ); document.write( "\".05n+%2B+.1d+=+3.50\" The coins add up to $3.50
\n" ); document.write( "multiply this equation by 10
\n" ); document.write( "\".5n+%2B+d+=+35\"
\n" ); document.write( "Subtract this equation from the 1st one
\n" ); document.write( "\".5n+=+15\"
\n" ); document.write( "\"n+=+30\" answer
\n" ); document.write( "\"n+%2B+d+=+50\"
\n" ); document.write( "\"30+%2B+d+=+50\"
\n" ); document.write( "\"d+=+20\" answer
\n" ); document.write( "Ther are 30 nickels and 20 dimes
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