document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=16433>Question 16433</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has 2.5 liters of a solution which is 70% acid. How much water should be added to obtain a 50% acid solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #8003 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=8003\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  chemist has 2.5 liters of a solution which is 70% acid. How much water should be added to obtain a 50% acid solution?<BR>\n" );
document.write( "  qty.of solution = 2.5 l<BR>\n" );
document.write( "   % acid in solution = 70<BR>\n" );
document.write( "   hence qty.of acid in the solution = 2.5*70/100 = 1.75 l<BR>\n" );
document.write( "   required percentage = 50<BR>\n" );
document.write( "   let the water to be added = x l<BR>\n" );
document.write( "    total qty.of solution = (2.5+x) l<BR>\n" );
document.write( "    qty of acid =  same as before = 1.75 l<BR>\n" );
document.write( "    % acid in the new solution = 1.75*100/(2.5+x) = 50 as given<BR>\n" );
document.write( "        175= 50(2.5+x)<BR>\n" );
document.write( "       2.5+x = 175/50 = 3.5<BR>\n" );
document.write( "      x= 3.5 - 2.5 = 1  litre<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );