document.write( "Question 1174754: Find sin(2a) when a terminates in quadrant II. cosa=-4/5. (I got -24/25, but I am not sure if I solved it correctly) \n" ); document.write( "
Algebra.Com's Answer #800231 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "you got it right!\r
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\n" ); document.write( "\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( "\"sin%282a%29\"
\n" ); document.write( "\"cos%28a%29=-4%2F5\"\r
\n" ); document.write( "\n" ); document.write( "when a terminates in quadrant \"II\", \"0%3C=+a+%3C=180\"\r
\n" ); document.write( "\n" ); document.write( "use identity:\r
\n" ); document.write( "\n" ); document.write( "\"sin%5E2%28a%29=1-cos%5E2%28a%29\".........substitute \"cos%28a%29=-4%2F5\"
\n" ); document.write( "\"sin%5E2%28a%29=1-%28-4%2F5%29%5E2\"
\n" ); document.write( "\"sin%5E2%28a%29=1-%2816%2F25%29\"
\n" ); document.write( "\"sin%5E2%28a%29=25%2F25-16%2F25\"
\n" ); document.write( "\"sin%5E2%28a%29=9%2F25\"
\n" ); document.write( "\"sin%28a%29=sqrt%289%2F25%29\"\r
\n" ); document.write( "\n" ); document.write( "then \"sin%28a%29+=+3%2F5\" or \"sin%28a%29+=-+3%2F5\"\r
\n" ); document.write( "\n" ); document.write( "use identity:\r
\n" ); document.write( "\n" ); document.write( "\"sin%282a%29=2+sin%28a%29+cos%28a%29+\"..........substitute \"sin%28a%29\" and\"+cos%28a%29\"\r
\n" ); document.write( "\n" ); document.write( " note: since \"a\" is in quadrant \"II\", the info leads to\"+sin%28a%29+=++3%2F5\",so we have\r
\n" ); document.write( "\n" ); document.write( "\"sin%282a%29=2+%283%2F5%29%28-4%2F5%29\"
\n" ); document.write( "\"sin%282a%29=-24%2F25\"\r
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