document.write( "Question 1174700: A box contains 15 items, 4 of which are defective. Three items are selected. What is the probability that the first is good, the second is defective and third is also good. \n" ); document.write( "
Algebra.Com's Answer #800160 by Theo(13342)![]() ![]() You can put this solution on YOUR website! there are 15 items in the box. \n" ); document.write( "4 of them are defective. \n" ); document.write( "11 of them are not.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the probability that the first item you pick out of the box is not defective is 11/15.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "assuming the first item you picked out of the box was not defective, then the box now contains 14 items. \n" ); document.write( "4 of them are defective. \n" ); document.write( "10 of them are not.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the probability that the second item you pick out of the box is defective is 4/14.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "assuming the second items you picked out of the box was defective, then the box now contains 13 items. \n" ); document.write( "3 of them are defective. \n" ); document.write( "10 of them are not.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the probability that the third item you pick out of the box is not defective is 10/13.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the probability that all 3 events occur is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "11/15 * 4/14 * 10/13 = (11*4*10) / (15*14*13) = 440 / 2730 = 4.1611721612.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |