document.write( "Question 1174700: A box contains 15 items, 4 of which are defective. Three items are selected. What is the probability that the first is good, the second is defective and third is also good. \n" ); document.write( "
Algebra.Com's Answer #800160 by Theo(13342)\"\" \"About 
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there are 15 items in the box.
\n" ); document.write( "4 of them are defective.
\n" ); document.write( "11 of them are not.\r
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\n" ); document.write( "\n" ); document.write( "the probability that the first item you pick out of the box is not defective is 11/15.\r
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\n" ); document.write( "\n" ); document.write( "assuming the first item you picked out of the box was not defective, then the box now contains 14 items.
\n" ); document.write( "4 of them are defective.
\n" ); document.write( "10 of them are not.\r
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\n" ); document.write( "\n" ); document.write( "the probability that the second item you pick out of the box is defective is 4/14.\r
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\n" ); document.write( "\n" ); document.write( "assuming the second items you picked out of the box was defective, then the box now contains 13 items.
\n" ); document.write( "3 of them are defective.
\n" ); document.write( "10 of them are not.\r
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\n" ); document.write( "\n" ); document.write( "the probability that the third item you pick out of the box is not defective is 10/13.\r
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\n" ); document.write( "\n" ); document.write( "the probability that all 3 events occur is:\r
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\n" ); document.write( "\n" ); document.write( "11/15 * 4/14 * 10/13 = (11*4*10) / (15*14*13) = 440 / 2730 = 4.1611721612.\r
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