document.write( "Question 1174700: A box contains 15 items, 4 of which are defective. Three items are selected. What is the probability that the first is good, the second is defective and third is also good. \n" ); document.write( "
Algebra.Com's Answer #800159 by AnlytcPhil(1806)\"\" \"About 
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document.write( "Here is a list of all eight possible ways to select the items:\r\n" );
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document.write( "      first        second       third    \r\n" );
document.write( "1.    good         good         good   \r\n" );
document.write( "2.    good         good       defective\r\n" );
document.write( "3.    good       defective      good   \r\n" );
document.write( "4.    good       defective    defective\r\n" );
document.write( "5.  defective      good         good   \r\n" );
document.write( "6.  defective      good       defective\r\n" );
document.write( "7.  defective    defective      good   \r\n" );
document.write( "8.  defective    defective    defective\r\n" );
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document.write( "Notice that there was only 1 successful way, number 3, which is in red.\r\n" );
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document.write( "That's 1 successful way out of 8 possible ways, so the probability is\r\n" );
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document.write( "1 out of 8, so we make that into a fraction 1/8.\r\n" );
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document.write( "Answer: 1/8\r\n" );
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document.write( "Edwin
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