document.write( "Question 1174603: In how many ways can five patients be accommodated in a hospital ward with 10 beds? \n" ); document.write( "

Algebra.Com's Answer #800036 by ikleyn(52803) $\"\"$ $\"About$

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document.write( "1st patient occupies any of          10 beds   (10 options)\r\n" );
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document.write( "2nd patient occupies any of remaining 9 beds   (9 options)\r\n" );
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document.write( "3rd patient occupies any of remaining 8 beds   (8 options)\r\n" );
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document.write( "4th patient occupies any of remaining 7 beds   (7 options)\r\n" );
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document.write( "5th patient occupies any of remaining 6 beds   (6 options)\r\n" );
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document.write( "THEREFORE, there are  10*9*8*7*6 = 30240 different ways to accommodate.     ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "The product of 5 sequential integer numbers in descending order, starting from the number 10.\r
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