document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1174586>Question 1174586</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Make a the subject of the formula in s=n\2[2a+(n-1)d]<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #800011 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=800011\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve for a.<BR>\n" );
document.write( "Isolate a<BR>\n" );
document.write( "get rid of the fraction <BR>\n" );
document.write( "2s=n (2a+(n-1)d)<BR>\n" );
document.write( "(2s/n)-(n-1)d=2a<BR>\n" );
document.write( "(s/n)-[(n-1)d]/2=a<BR>\n" );
document.write( "--<BR>\n" );
document.write( "check by using the arithmetic series (the formula is for the sum of one) 1,3,5,7,9,11,13,15<BR>\n" );
document.write( "s=(8/2)(2+(7(2))<BR>\n" );
document.write( "=4(16)<BR>\n" );
document.write( "=64<BR>\n" );
document.write( "-<BR>\n" );
document.write( "now solve for the first term<BR>\n" );
document.write( "(64/8)-(7*2)/2=8-7=1 </SPAN>\n" );
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