document.write( "Question 1174529: The probability that Nasim will study for her test is 3/10. The probability that she'll pass if she studies is 9/10. The probability that she'll pass if she doesn't study is 2/10. What is the probability that she has studied, given that she passes? \n" ); document.write( "
Algebra.Com's Answer #800010 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Studying and not studying are complementary events, so P(study)=3/10 means P(not study)=7/10. Then \n" ); document.write( "P(study and pass) = (3/10)(9/10) = 27/100 \n" ); document.write( "P(not study and pass) = (7/10)(2/10) = 14/100 \n" ); document.write( "P(pass) = 27/100+14/100 = 41/100 \n" ); document.write( "P(pass|study) = (27/100)/(41/100) = 27/41 \n" ); document.write( " \n" ); document.write( " |