document.write( "Question 1174584: If cot ฮธ=-2/9, cos ฮธ > 0; csc 0. Find the value of the indicated function.
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Algebra.Com's Answer #800006 by Abdulfatai Lanre(2)![]() ![]() You can put this solution on YOUR website! Cot๐=-2/9. \n" ); document.write( "Recall that cot๐=1/tan๐ \n" ); document.write( "1/tan๐=-2/9. \n" ); document.write( "Cross multiplying,we have \n" ); document.write( "9x1=-2tan๐ \n" ); document.write( "9=-2tan๐ \n" ); document.write( "9/-2=tan๐ \n" ); document.write( "-4.5=tan๐ \n" ); document.write( "tan๐=-4.5 \n" ); document.write( "๐=arctan(4.5) \n" ); document.write( "๐=77.45 \n" ); document.write( "๐ approx. 77.5(1dp) \n" ); document.write( "cos๐ > 0. \n" ); document.write( "Cos77. 5 > 0. \n" ); document.write( "O.216 > 0.True \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |