document.write( "Question 1174584: If cot ฮธ=-2/9, cos ฮธ > 0; csc 0. Find the value of the indicated function.
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Algebra.Com's Answer #800006 by Abdulfatai Lanre(2)\"\" \"About 
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Cot๐ˆš=-2/9.
\n" ); document.write( "Recall that cot๐ˆš=1/tan๐ˆš
\n" ); document.write( "1/tan๐ˆš=-2/9.
\n" ); document.write( "Cross multiplying,we have
\n" ); document.write( "9x1=-2tan๐ˆš
\n" ); document.write( "9=-2tan๐ˆš
\n" ); document.write( "9/-2=tan๐ˆš
\n" ); document.write( "-4.5=tan๐ˆš
\n" ); document.write( "tan๐ˆš=-4.5
\n" ); document.write( "๐ˆš=arctan(4.5)
\n" ); document.write( "๐ˆš=77.45
\n" ); document.write( "๐ˆš approx. 77.5(1dp)
\n" ); document.write( "cos๐ˆš > 0.
\n" ); document.write( "Cos77. 5 > 0.
\n" ); document.write( "O.216 > 0.True \r
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