document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1174490>Question 1174490</A>: <I><SPAN STYLE=\"word-break: break-all;\"> test walks 2km by 6:00 a.m.she walks 4km by 8:00 a.m. if she continues at this rate,how many far will she walk by 9:00 a.m. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #799989 by </B><A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><B>amarjeeth123(569)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=799989\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> test walks 2km by 6:00 a.m.she walks 4km by 8:00 a.m.<BR>\n" );
document.write( "So she walks 2km in 2 hours.<BR>\n" );
document.write( "Speed =distance/time=2/2=1 kmph.<BR>\n" );
document.write( "She will walk another 1km by 9:00 am.<BR>\n" );
document.write( "She would have walked 5km in total by 9:00 a.m.<BR>\n" );
document.write( "Answer=5km by 9:00 a.m. </SPAN>\n" );
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