document.write( "Question 1174562: Choose a new vehicle sold in the United States in November 2014 at random. The probability distribution for the type of vehicle chosen is given below.\r
\n" ); document.write( "\n" ); document.write( "Vehicle type and Probability:
\n" ); document.write( "Passenger Car 0.46 - Pickup Truck 0.15 - SUV 0.10 - Crossover ? - Minivan 0.05\r
\n" ); document.write( "\n" ); document.write( "1) What is the probability that the vehicle is a crossover?
\n" ); document.write( "2) Given that the vehicle is not a passenger car, what is the probability that it is a pickup truck?
\n" ); document.write( "3) What is the probability that the vehicle is a pickup truck, SU, or minivan?
\n" ); document.write( "Using the same information as the last question. Suppose you select 3 vehicles at random. You want to know the probability that the vehicles are of three different types. Describe how you would carry out a simulation to help answer this question. Do not actually perform the simulation. \n" ); document.write( "
Algebra.Com's Answer #799982 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Hi\r\n" );
document.write( "Passenger Car 0.46 - Pickup Truck 0.15 - SUV 0.10 - Crossover .24 - Minivan 0.05\r\n" );
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document.write( "P(crossover) = 1 - .46 -.15 - .10 - .05 = .24\r\n" );
document.write( "P(pickup|Not car) = .15/.54\r\n" );
document.write( "P(pickup truck, SU, or minivan) = .15 + .10 + .05\r\n" );
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document.write( "Select 3: the probability that the vehicles are of three different types\r\n" );
document.write( "Yes,  5C3 0r 10 ways of selecting a trio from 5 types.\r\n" );
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document.write( "P(of each trio)... would be the product of their individual probabilities\r\n" );
document.write( "Total Probability(vehicles are of three different types) would be the sum of\r\n" );
document.write( "each of the possible trios. \r\n" );
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document.write( "Wish You the Best in your Studies.\r\n" );
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