document.write( "Question 109751: factor
\n" ); document.write( "L(squared)-16L+60=0
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Algebra.Com's Answer #79996 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"L%5E2-16L%2B60=0\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"%28L-10%29%28L-6%29=0\" Factor the left side (note: if you need help with factoring, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "Now set each factor equal to zero:\r
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\n" ); document.write( "\n" ); document.write( "\"L-10=0\" or \"L-6=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"L=10\" or \"L=6\" Now solve for L in each case\r
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\n" ); document.write( "\n" ); document.write( "So our solutions are \"L=10\" or \"L=6\"\r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph \"y=L%5E2-16L%2B60\" we get\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28500%2C500%2C-8%2C12%2C-8%2C12%2C+x%5E2-16x%2B60%29+\"\r
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\n" ); document.write( "\n" ); document.write( "and we can see that the graph has roots at \"L=10\" and \"L=6\", so this verifies our answer.\r
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