document.write( "Question 1174543: Nithya has money invested in 3 accounts: Account A earns 3% interest, Account B earns 4%, and Account C earns 5%. The money invested in Account B is 4,000 less than the money in account A. The money invested in Account C is twice the amount in Account A. A total of $1,540 was earned in total interest for the year. What was the total amount of money invested between the 3 accounts at the start of the year?
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document.write( "I tried this:
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document.write( "x=account A, y= account B, z= account C
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document.write( " 0.03x=0.04y+4,000
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document.write( "0.05z=0.06x
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document.write( "0.03x+0.04y+0.05z=1540
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document.write( "But some numbers were negative. What's wrong with my equations? \n" );
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Algebra.Com's Answer #799957 by MathTherapy(10552)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Nithya has money invested in 3 accounts: Account A earns 3% interest, Account B earns 4%, and Account C earns 5%. The money invested in Account B is 4,000 less than the money in account A. The money invested in Account C is twice the amount in Account A. A total of $1,540 was earned in total interest for the year. What was the total amount of money invested between the 3 accounts at the start of the year? \n" ); document.write( "I tried this: \n" ); document.write( "x=account A, y= account B, z= account C \n" ); document.write( " 0.03x=0.04y+4,000 \n" ); document.write( "0.05z=0.06x \n" ); document.write( "0.03x+0.04y+0.05z=1540 \n" ); document.write( "But some numbers were negative. What's wrong with my equations? \n" ); document.write( " I agree with Tutor @IKLEYN that 1 variable is sufficient to solve problems such as this one.\r\n" ); document.write( " |