document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1174531>Question 1174531</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Line l is perpendicular to the graph of 2x + 3y = 5, and has the same x-intercept as the graph of 2x + 3y = 5. Find the standard form of the equation whose graph is l.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #799943 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=799943\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x+3y=5 is y=(-2/3)x+(5/3), with slope -2/3 and y-intercept (5/3).  The x-intercept is when y=0 and is 2.5<BR>\n" );
document.write( "The perpendicular line has slope 3/2, the negative reciprocal.<BR>\n" );
document.write( "We know that a point on that line is (2.5, 0) from the first line.<BR>\n" );
document.write( "point-slope formula y=y1=m(x-x1), m slope (x1, y1) point<BR>\n" );
document.write( "y-0=(3/2)(x-2.5)<BR>\n" );
document.write( "y=(3/2)x-3.75<BR>\n" );
document.write( "or (3/2)x-y=3.75 and standard form 12x-8y=30<BR>\n" );
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