document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1174525>Question 1174525</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An amateur cyclist is training for a road race. He rode the first 27-mile portion of his workout at a constant rate. He then reduced his speed by 3 mph for the remaining 18-mile cool-down portion of the workout. Each portion of the workout took equal time. Find the cyclist's rate during the first portion and his rate during the cool-down portion.<BR>\n" );
document.write( "First Portion:  mph <BR>\n" );
document.write( "Cool-Down:  mph </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #799939 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=799939\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d=s*t<BR>\n" );
document.write( "27=s*t<BR>\n" );
document.write( "18=(s-3)*t, since the time for each part is the same<BR>\n" );
document.write( "t=27/s<BR>\n" );
document.write( "t=18/(s-3)<BR>\n" );
document.write( "so 27/s=18/(s-3)<BR>\n" );
document.write( "cross-multiply  and 27s-81=18s<BR>\n" );
document.write( "9s=81<BR>\n" );
document.write( "s=9 mph initially for 3 hours to do 27 miles<BR>\n" );
document.write( "s-3=6 mph for 3 hours to do 18 miles<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );