document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1174496>Question 1174496</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with this question,How many grams of pure water must be added to 40 grams of a 10% saline solution to make a saline solution that is 5% salt? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #799916 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=799916\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many grams of pure water must be added to 40 grams of a 10% saline solution to make a saline solution that is 5% salt?<BR>\n" );
document.write( "Very easy, the amt of salt does not change only the amt of liquid<BR>\n" );
document.write( ".10(40) = .05(w+40)<BR>\n" );
document.write( "4 = .05w + 2<BR>\n" );
document.write( "4 - 2 = .05w<BR>\n" );
document.write( "2 = .05w<BR>\n" );
document.write( "w = 2/.05<BR>\n" );
document.write( "w = 40 grams to be added, which is what you would expect if you half the percent </SPAN>\n" );
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