document.write( "Question 1174401: Assuming that the samples come from normal distributions, find the margin of error given the following:
\n" ); document.write( "A.n=10, sample mean= 28, s=4.0, 90% confidence
\n" ); document.write( "B.n= 16, sample mean=50, s=4.2, 95% confidence \n" ); document.write( "
Algebra.Com's Answer #799910 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "Hi\r\n" );
document.write( "Note Table Below:\r\n" );
document.write( "ME =\"+z%2Asigma%2Fsqrt%28n%29\"\r\n" );
document.write( "A.n=10, sample mean= 28, s=4.0, 90% confidence\r\n" );
document.write( " ME =\"+1.645%2A4%2Fsqrt%2810%29\"\r\n" );
document.write( "28 - ME < \"mu\" < 28 + ME\r\n" );
document.write( "\r\n" );
document.write( "B.n= 16, sample mean=50, s=4.2, 95% confidence\r\n" );
document.write( "   ME =\"+1.96%2A4.2%2Fsqrt%2816%29\"\r\n" );
document.write( "50 - ME < \"mu\" < 50 + ME\r\n" );
document.write( "\r\n" );
document.write( "Wish You the Best in your Studies.\r\n" );
document.write( "\r\n" );
document.write( " = CI	z = value\r\n" );
document.write( "90%	z =1.645\r\n" );
document.write( "92%	z = 1.751\r\n" );
document.write( "95%	z = 1.96\r\n" );
document.write( "98%	z = 2.326\r\n" );
document.write( "99%	z = 2.576\r\n" );
document.write( "

\n" ); document.write( " \n" ); document.write( "
\n" );