document.write( "Question 1174478: hey, I need ASAP help with this if you could please answer each part detailed and clear that would be very helpful! thankyou:)\r
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document.write( "A hydro pole is supported by a 20m guy wire
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document.write( "that makes an angle of 48° with the level ground. A 16m guy wire is to be fastened to the other
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document.write( "side of the pole for reinforcement. Both wires are attached to the pole at the top.
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document.write( "a. What angle should the second wire make with the ground? Round your answer to the
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document.write( "nearest degree.
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document.write( "b. How tall is the hydro pole? Round your answer to the nearest tenth of a metre.
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document.write( "c. How far is the base of the 20m guy wire from the base of the 16m guy wire? Round your
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document.write( "answer to the nearest tenth of a metre.
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Algebra.Com's Answer #799901 by Theo(13342) You can put this solution on YOUR website! label your triangle ABCD. \n" ); document.write( "A is the foot of the bottom of the 16 foot wire. \n" ); document.write( "B is the top of the pole \n" ); document.write( "C is the foot of the bottom of the 20 foot wire. \n" ); document.write( "D is the base of the pole.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the height of the pole is BD. \n" ); document.write( "the angle that the second wire makes with the ground is angle BAD. \n" ); document.write( "the angle that the first wire makes with the ground is angle BCD. \n" ); document.write( "the distance between the bottom of the 20 meter wire and the bottom of the 16 meter wire is AC. AC is the sum of AD and DC. \n" ); document.write( "the length of BC is given as 20 meters. \n" ); document.write( "the length of AB is given as 16 meters.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to find the height of the pole, use sin(48) = BD / 20 \n" ); document.write( "solve for BD to get BD = 20 * sin(48) = 14.86289651 meters.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to find the angle that the 16 meter pole makes with the ground, use angle BAD = arcsin(BD/16) = arcsin(14.86289651/16) = 68.26879086 degrees.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to find the length of AD, use 16^2 - BD^2 = 16^2 - 14.86289651^2 = AD^2 and then take the square root of that to find AD = 5.924044847.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to find the length of DC, use 20^2 - BD^2 = 20^2 - 14.86289651^2 = DC^2 and then take the square root of that to find DC = 13.38261213.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "those are your answers.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's a picture to help you see where everything fits.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your solutions are in the picture rounded to 1 d3ecimal place.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i'll be available to answer any questions you night have regarding this.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "theo\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |