document.write( "Question 1174417: rob's school is selling tickets to a play.on the first day of ticket sales the school sold 9 adult tickets and 8 child tickets for a total of $145. the school took in $82 on the second day by selling 2 adult tickets and 8 child tickets.what is the price each of one adult ticket and one child ticket? \n" ); document.write( "
Algebra.Com's Answer #799886 by greenestamps(13198)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Formally.... \n" ); document.write( "x = cost of each child ticket \n" ); document.write( "y = cost of each adult ticket \n" ); document.write( "9x+8y = 145 (1st day total sales) \n" ); document.write( "2x+8y = 82 (2nd day total sales) \n" ); document.write( "Solve by subtracting the second equation from the first, giving \n" ); document.write( "7x = 63 \n" ); document.write( "Use that to find the cost of each adult ticket, x; then use that value with the total sales for either day to find the cost of each child ticket. \n" ); document.write( "That's a simple example of an algebraic solution. You can get the answer informally by doing exactly the same calculations without the formal algebra. \n" ); document.write( "9 adult tickets and 8 child tickets for $145, and 2 adult tickets and 8 child tickets for $82, means 9-2=7 adult tickets cost $145-$82 = $63. \n" ); document.write( "7 adult tickets for $63 means $63/7 = $9 for each one. \n" ); document.write( "2 adult tickets and $9 each, for a total of $18, plus 8 child tickets for a total of $82, means 8 child tickets for $82-$18 = $64 \n" ); document.write( "8 child tickets for $64 means $64/8 = $8 for each one. \n" ); document.write( " \n" ); document.write( " |