document.write( "Question 1174417: rob's school is selling tickets to a play.on the first day of ticket sales the school sold 9 adult tickets and 8 child tickets for a total of $145. the school took in $82 on the second day by selling 2 adult tickets and 8 child tickets.what is the price each of one adult ticket and one child ticket? \n" ); document.write( "
Algebra.Com's Answer #799886 by greenestamps(13198)\"\" \"About 
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\n" ); document.write( "Formally....

\n" ); document.write( "x = cost of each child ticket
\n" ); document.write( "y = cost of each adult ticket

\n" ); document.write( "9x+8y = 145 (1st day total sales)
\n" ); document.write( "2x+8y = 82 (2nd day total sales)

\n" ); document.write( "Solve by subtracting the second equation from the first, giving
\n" ); document.write( "7x = 63

\n" ); document.write( "Use that to find the cost of each adult ticket, x; then use that value with the total sales for either day to find the cost of each child ticket.

\n" ); document.write( "That's a simple example of an algebraic solution. You can get the answer informally by doing exactly the same calculations without the formal algebra.

\n" ); document.write( "9 adult tickets and 8 child tickets for $145, and 2 adult tickets and 8 child tickets for $82, means 9-2=7 adult tickets cost $145-$82 = $63.
\n" ); document.write( "7 adult tickets for $63 means $63/7 = $9 for each one.
\n" ); document.write( "2 adult tickets and $9 each, for a total of $18, plus 8 child tickets for a total of $82, means 8 child tickets for $82-$18 = $64
\n" ); document.write( "8 child tickets for $64 means $64/8 = $8 for each one.

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