document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=109743>Question 109743</A>: <I><SPAN STYLE=\"word-break: break-all;\"> We have to build and igloo out of 1 gallon jugs for class.  It will have an interior diameter of 6 feet + an entry which is a cylender shape on it's side that is to be 3 feet wide and 3 feet long.  How do I calculate the outside area so that once I have the demensions of the milk jugs, I can determine how many jugs I need... It would be a dome with an open ended 1/2 cylender?/? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #79987 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=79987\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the outside area would depend on the size of the milk jugs\r<BR>\n" );
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document.write( "the inside area is the surface area of a hemisphere with a radius of 3 feet<BR>\n" );
document.write( "... S.A.=(4(pi)r^2)/2\r<BR>\n" );
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document.write( "the same idea applies to the entry<BR>\n" );
document.write( "... the inside area is the surface of a half cylinder 3 feet long, with a diameter of 3 feet<BR>\n" );
document.write( "... S.A.=(D(pi)L)/2\r<BR>\n" );
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document.write( "depending on how the entry \"matches up\" with the dome, there may be an adjustment necessary in the number of jugs<BR>\n" );
document.write( "... the jugs from the entry opening in the dome will probably be enough to connect the entry to the dome </SPAN>\n" );
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