document.write( "Question 1174392: Please help me with this problem :
\n" ); document.write( "The length of a rectangular lot is 14 meters less than twice the lot’s width. The owner decided to decrease
\n" ); document.write( "the length and the width by 3 meters each for landscaping purposes. The perimeter of the smaller
\n" ); document.write( "rectangular lot is 80 meters. What is the area of the original lot in square meters? \n" ); document.write( "
Algebra.Com's Answer #799840 by ankor@dixie-net.com(22740)\"\" \"About 
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The length of a rectangular lot is 14 meters less than twice the lot’s width.
\n" ); document.write( "w = the original width
\n" ); document.write( "L = (2w - 14); the original length
\n" ); document.write( ":
\n" ); document.write( " The owner decided to decrease the length and the width by 3 meters each for landscaping purposes.
\n" ); document.write( "(w-3) = the new width
\n" ); document.write( "and
\n" ); document.write( "(2w-14) - 3 = (2w-17), the new length
\n" ); document.write( ":
\n" ); document.write( " The perimeter of the smaller rectangular lot is 80 meters.
\n" ); document.write( "2(2w-17) + 2(w-3) = 80
\n" ); document.write( "simplify, divide by 2
\n" ); document.write( "2w - 17 + w - 3 = 40
\n" ); document.write( "3w - 20 = 40
\n" ); document.write( "3w = 40 + 20
\n" ); document.write( "3w = 60
\n" ); document.write( "w = 60/3
\n" ); document.write( "w = 20 meter, the original width
\n" ); document.write( "and
\n" ); document.write( "2(20) - 14 = 26 meters the original length
\n" ); document.write( ":
\n" ); document.write( " What is the area of the original lot in square meters?
\n" ); document.write( "26 * 20 = 520 sq/meters
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "check by finding the new perimeter 23 by 17
\n" ); document.write( "2(17) + 2(23) =
\n" ); document.write( "34 + 46 = 80
\n" ); document.write( " \n" ); document.write( "
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