document.write( "Question 109749This question is from textbook algebra2 with trigonometry
\n" ); document.write( ": Two factors of \"x%5E3-3x%5E2-4x%2B12\" are \"x%2B2\" and \"x-3\". Find the remaining factor. My answer was x+3 but i am not so sure, can you please help and explain the problem to me? thank you. \n" ); document.write( "
Algebra.Com's Answer #79980 by scott8148(6628)\"\" \"About 
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the easiest way is to look at the constant term (12)
\n" ); document.write( "... the constants in the three factors must multiply to this value\r
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\n" ); document.write( "\n" ); document.write( "so, for x+? ... (2)*(-3)*(?)=12
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