document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=16407>Question 16407</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. 4(1-2x)+3=79<BR>\n" );
document.write( "2. 4a+5[1-3(2a-1)]=2(2a+5) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #7997 by </B><A HREF=/tutors/aboutme.mpl?userid=tjnw79><B>tjnw79(57)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tjnw79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=7997\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. 4(1-2x)+3=79\r<BR>\n" );
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document.write( "First you want to time 4 by everthing in the () so that would be (4*1)-(4*2x) to get (4-8x)+3=79. <BR>\n" );
document.write( "Add 4 and 3 together\r<BR>\n" );
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document.write( "7-8x=79<BR>\n" );
document.write( "Subtract 7 on both sides<BR>\n" );
document.write( "-8x=72<BR>\n" );
document.write( "divide by -8 on both sides\r<BR>\n" );
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document.write( "Answer x=-9\r<BR>\n" );
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