document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1174282>Question 1174282</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a recipe calls for 5 cups of sugar for every 12 litres of milk.  How much sugar do you need is you are using 15 litres of milk<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #799693 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=799693\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Both responses you have received so far use the same algebraic approach, using a proportion.<br><BR>\n" );
document.write( "I personally find it easier and faster to solve the problem informally.<br><BR>\n" );
document.write( "The change from 12L of milk to 15L is an increase by a factor of 15/12 = 5/4, so you need to increase the amount of sugar by a factor of 5/4.<br><BR>\n" );
document.write( "ANSWER: (5/4)*5 = 25/4 = 6.25 cups of sugar for 15L of milk<br><BR>\n" );
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