document.write( "Question 1174277: write an equation of the line that passes through (5, -4) and is parallel to y=2x+3 \n" ); document.write( "

Algebra.Com's Answer #799683 by math_helper(2461) $\"\"$ $\"About$

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document.write( "y = 2x+3 has the form  y = mx + b  (m=slope, b=y-intercept).\r
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document.write( "Parallel lines will have the equal slopes.\r
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document.write( "So we know this much: the parallel line has the form:  y = 2x + b\r
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document.write( "You can either use the point (5,-4) to solve for b, or you
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document.write( "can use the point-slope form of a line  y-y0 = m(x-x0) and 
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document.write( "plug in (5,-4) for (x0,y0).\r
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document.write( "Solving for b:
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document.write( "      -4 = 2(5) + b  --> b = -14  ==> eqn is y = 2x - 14\r
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document.write( "Using point-slope form:
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document.write( "       y - (-4) = 2(x - 5)
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document.write( "       y + 4 = 2x - 10
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document.write( "          y = 2x - 14    (same result)\r
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