document.write( "Question 1174243: For the system of equations :
\n" ); document.write( "x+2y+3z=73
\n" ); document.write( "3x+y+z=49
\n" ); document.write( "2x+3y+4z=106
\n" ); document.write( "In matrix form AX=B,the inverse matrix A^-1 is A^-1 = 1/2 [ 1 1 -1
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\n" ); document.write( "Use A^-1 to solve the system. Show all work.
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Algebra.Com's Answer #799650 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Hi\r\n" );
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document.write( "\"A=+%28matrix%283%2C3%2C1%2C2%2C3%2C3%2C1%2C1%2C2%2C3%2C4%29%29\"\r\n" );
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document.write( "\"A%5E%28-1%29+=+%281%2F2%29%28matrix%283%2C3%2C1%2C1%2C-1%2C-10%2C-2%2C8%2C7%2C1%2C-5%29%29\"\r\n" );
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document.write( "  \"%28matrix%283%2C3%2C1%2C1%2C-1%2C-10%2C-2%2C8%2C7%2C1%2C-5%29%29\" *\"%28matrix%283%2C1%2C73%2C49%2C106%29%29\" =\"%28matrix%283%2C1%2C16%2C20%2C30%29%29\"\r\n" );
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document.write( "Note:\r\n" );
document.write( "   (1)73 + (1)49 + (-1) 106 = 16\r\n" );
document.write( "  -730  - 98 + (8)106 = 20  \r\n" );
document.write( "   (7)73 + 49 + (-5)106= 30\r\n" );
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document.write( " (1/2)\"%28matrix%283%2C1%2C16%2C20%2C30%29%29\"  = \"%28matrix%283%2C1%2C8%2C10%2C15%29%29\"\r\n" );
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document.write( "   (8,10,15)  the solution for this system of Equations\r\n" );
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document.write( "Wish You the Best in your Studies.\r\n" );
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