document.write( "Question 1174236: How many liters of a 24 percent alcohol solution must be mixed with 20 liters of a 46 percent alcohol solution to get a 28 percent alcohol solution?
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Algebra.Com's Answer #799639 by ankor@dixie-net.com(22740)\"\" \"About 
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How many liters of a 24 percent alcohol solution must be mixed with 20 liters of a 46 percent alcohol solution to get a 28 percent alcohol solution?
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\n" ); document.write( "let a = amt of 24% alcohol required
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\n" ); document.write( ".24a + .46(20) = .28(a+20)
\n" ); document.write( ".24a + 9.2 = .28a + 5.6
\n" ); document.write( "9.2 - 5.6 = .28a - .24a
\n" ); document.write( "3.6 = .04a
\n" ); document.write( "a = 3.6/.04
\n" ); document.write( "a = 90 liters of 24% alcohol required
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\n" ); document.write( ".24(90) + .46(20) = .28(90+20)
\n" ); document.write( "21.6 + 9.2 = .28(110)
\n" ); document.write( "30.2 = 30.2
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