document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1174188>Question 1174188</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5. The energy of a moving body varies directly as the square of its speed. If a body has energy of 5 units at a speed of 3 feet per second, what is its speed when its energy is 20 units? (show complete solution thanks!) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #799624 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=799624\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> E=k*s^2<BR>\n" );
document.write( "5=k*3^2<BR>\n" );
document.write( "k=(5/9)<BR>\n" );
document.write( "-<BR>\n" );
document.write( "Now use k in the next equation<BR>\n" );
document.write( "20=(5/9)*s^2<BR>\n" );
document.write( "s^2=20(9/5)=36 units<BR>\n" );
document.write( "s=6 units<BR>\n" );
document.write( "-<BR>\n" );
document.write( "Can check this by noting that speed doubled from 3 ft/sec to 6 ft/sec and energy therefore should quadruple from 5 units to 20 units.<BR>\n" );
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