document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1174191>Question 1174191</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A product estimate that 3% of his output of a small items is defective.find the probabilities that in a sample of 10 item<BR>\n" );
document.write( "a).less than two <BR>\n" );
document.write( "b). More than two items will be defective </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #799620 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=799620\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Fewer than 2 is 0 or 1<BR>\n" );
document.write( "p(0) defective is 0.97^10=0.7374<BR>\n" );
document.write( "p(1) defective is 10*0.97^9*0.03=0.2281<BR>\n" );
document.write( "the answer is the sum of the probabilities or 0.9655<BR>\n" );
document.write( "-<BR>\n" );
document.write( "more than 2 items will be defective is 1- probability p(0,1,2)<BR>\n" );
document.write( "calculator is 1-binomcdf(10,0.03,2)=0,0028. The 1- comes from the fact that the binomial function computes from the left side, and we want the right side for the answer.<BR>\n" );
document.write( "p(2)=45*0.97^8*0.03^2=0.0317<BR>\n" );
document.write( "add that to the first answer to get 0.9972, probability 0,1,2 items are defective.<BR>\n" );
document.write( "The answer is 1-0.9972 or 0.0028<BR>\n" );
document.write( "binompdf is a good one to remember, because that will give you the specific value, since remembering the top value to use for the interval can sometimes be confusing. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );