document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1174208>Question 1174208</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Determine the value of a so that the average rate of change of the function h(x)= x^2+3x+2 on the interval -3<=x<=a is -1. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #799601 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=799601\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Average rate of change = (h(x2) - h(x1))/(x2 - x1), where the interval is [x1,x2]<BR>\n" );
document.write( "-1 = a^2 + 3a + 2 - ((-3)^2 - 3*3 + 2)/(a - -3)<BR>\n" );
document.write( "-1 = (a^2 + 3a)/(a + 3) = a(a + 3)/(a + 3) = a<BR>\n" );
document.write( "Ans: a = -1 </SPAN>\n" );
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