document.write( "Question 109691: find the vertex of the parobola f(x)=-4x^2+40x-93 \n" ); document.write( "
Algebra.Com's Answer #79954 by jim_thompson5910(35256)\"\" \"About 
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To find the vertex, we need to know the axis of symmetry\r
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\n" ); document.write( "\n" ); document.write( "To find the axis of symmetry, use this formula:\r
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\n" ); document.write( "\n" ); document.write( "\"x=-b%2F%282a%29\"\r
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\n" ); document.write( "\n" ); document.write( "From the equation \"y=-4x%5E2%2B40x-93\" we can see that a=-4 and b=40\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-40%29%2F%282%2A-4%29\" Plug in b=40 and a=-4\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-40%29%2F-8\" Multiply 2 and -4 to get -8\r
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\n" ); document.write( "\n" ); document.write( "\"x=5\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "So the axis of symmetry is \"x=5\"\r
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\n" ); document.write( "\n" ); document.write( "So the x-coordinate of the vertex is \"x=5\". Lets plug this into the equation to find the y-coordinate of the vertex.\r
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\n" ); document.write( "\n" ); document.write( "Lets evaluate \"f%285%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29=-4x%5E2%2B40x-93\" Start with the given polynomial\r
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\n" ); document.write( "\n" ); document.write( "\"f%285%29=-4%285%29%5E2%2B40%285%29-93\" Plug in \"x=5\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%285%29=-4%2825%29%2B40%285%29-93\" Raise 5 to the second power to get 25\r
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\n" ); document.write( "\n" ); document.write( "\"f%285%29=-100%2B40%285%29-93\" Multiply 4 by 25 to get 100\r
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\n" ); document.write( "\n" ); document.write( "\"f%285%29=-100%2B200-93\" Multiply 40 by 5 to get 200\r
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\n" ); document.write( "\n" ); document.write( "\"f%285%29=7\" Now combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So the vertex is (5,7)\r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph the equation \"y=-4x%5E2%2B40x-93\" we get\r
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\n" ); document.write( "\n" ); document.write( "and we can see that the vertex is (5,7)
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