document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1174138>Question 1174138</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Iwas Realty is a real estate company selling homes in the Vancouver, British Columbia.<BR>\n" );
document.write( "The mean number of homes sold by the company per day is 2.<BR>\n" );
document.write( "a. What is the probability that the company sells exactly 3 homes tomorrow? <BR>\n" );
document.write( "b. Find the probability of selling more than 2 homes on a particular day?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #799537 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=799537\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> this is likely a Poisson distribution with parameter proportion to time, discrete variable, and theoretically infinite numbers.<BR>\n" );
document.write( "p(3)=e^(-2)*2^3/3!=0.1804<BR>\n" );
document.write( "-<BR>\n" );
document.write( "this is 1- probability (0,1,2)<BR>\n" );
document.write( "prob of 0 is e^(-2)=0.1353<BR>\n" );
document.write( "p(1) is e^(-2)*2^1/1=0.2707<BR>\n" );
document.write( "p(2)=e^(-2)*2^2/2!=0.2707<BR>\n" );
document.write( "That probability sum is 0.6767<BR>\n" );
document.write( "the answer of p(>2) is 0.3233<BR>\n" );
document.write( "also on calculator 1-poissoncdf(2,2) for the left side of the distribution. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );