document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1174081>Question 1174081</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An executive invests $28,000, some at 6% and the rest at 4% annual interest. If he receives an annual return of $1,440, how much is invested at each rate?<BR>\n" );
document.write( "at 6% interest	$  <BR>\n" );
document.write( "at 4% interest	$  <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #799485 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=799485\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is a quick and easy non-algebraic alternative to the standard formal algebraic solution provided by the other tutor.<br><BR>\n" );
document.write( "The algebraic solution is of course fine.  But if obtaining a solution quickly is beneficial and a formal algebraic solution is not required (as in a timed math competition), this alternative method is very useful.<br><BR>\n" );
document.write( "All $28,000 invested at 6% would earn $1680 interest.<BR>\n" );
document.write( "All invested at 4% would earn $1120 interest.<BR>\n" );
document.write( "The actual interest was $1440.<br><BR>\n" );
document.write( "Determine, perhaps with the help of a number line, that the actual interest $1440 is $320/$560 = 32/56 = 16/28 of the way from $1120 to $1680.<br><BR>\n" );
document.write( "That means 16/28 of the total was invested at the higher rate.  (Note I left 16/28 in unsimplified form, because the total investment was $28,000.<br><BR>\n" );
document.write( "ANSWER: 16/28 of the $28,000, or $16,000, was invested at the higher 6% interest rate; the other $12,000 was invested at 4%.<br><BR>\n" );
document.write( "CHECK: .06(16000)+.04(12000) = 960+480 = 1440<br><BR>\n" );
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