document.write( "Question 1174061: Rebecca is x years old.
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document.write( "Mary is 8 years older than Rebecca.
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document.write( "Jill is three times older than Mary.
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document.write( "The sum of their ages is 67.\r
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document.write( "Form an equation in terms of x\r
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document.write( "when you find x work out how old mary is \n" );
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Algebra.Com's Answer #799425 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Start with Rebecca, the youngest. \n" ); document.write( "R=x \n" ); document.write( "Mary=x+8 \n" ); document.write( "Jill is 3(x+8)=3x+24 \n" ); document.write( "They add to 67 \n" ); document.write( "so 5x+32=67 \n" ); document.write( "x=7 (Rebecca) \n" ); document.write( "Mary is is 15 \n" ); document.write( " |