document.write( "Question 16411: How do I find the slope and the y-intercept of this equation?\r
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Algebra.Com's Answer #7994 by rapaljer(4671)\"\" \"About 
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The y-intercept is the point where the graph crosses the y-axis. This is the point where x= 0. When the equation is given in this form, if you let x=0, then the y-intercept is just the constant term, which is -7.\r
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\n" ); document.write( "\n" ); document.write( "When the equation is written in this form, it turns out that the slope is the coefficient of x, which in this cse is 3/5. The slope means the rise over the run, or vertical distance over the horizontal distance.\r
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\n" ); document.write( "\n" ); document.write( "These two items make graphing the line very easy. Start by graphing the y intercept, by going down on the y-axis 7 units, and put a point.\r
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\n" ); document.write( "\n" ); document.write( "Next, with your pencil on that y-intercept, move up a rise of 3, then move from that point right 5 units and put the second point. Connect the two points, and you have your graph. It should look like this:\r
\n" ); document.write( "\n" ); document.write( "\"+graph+%28300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+%283%2F5%29%2Ax-7%29+\"\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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