document.write( "Question 1173984: A store sells televisions for $360 and digital video recorders for $270. At the beginning of the week its entire stock is worth $55,530. During the week it sells three quarters of the televisions and one third of the digital video recorders for a total of $32,310. How many televisions and digital video recorders did it have in its stock at the beginning of the week?\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #799377 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "x televisions and y video recorders

\n" ); document.write( "The value of the stock at the beginning of the week, at $360 for each television and $270 for each video recorder, was $55,530:

\n" ); document.write( "\"360x%2B270y+=+55530\"

\n" ); document.write( "The sales total for the week, consisting of 3/4 of the televisions and 1/3 of the video recorders, was $32,310:

\n" ); document.write( "\"360%283%2F4%29x%2B270%281%2F3%29y+=+32310\"
\n" ); document.write( "\"270x%2B90y+=+32310\"

\n" ); document.write( "Multiply the second equation by 3 and subtract the first equation to eliminate y and solve for x. Then use that x value in either original equation to find y.

\n" ); document.write( "
\n" ); document.write( "
\n" );