document.write( "Question 109653This question is from textbook
\n" ); document.write( ": Find f (-1/3). f(x)=18x2-12x-3 \n" ); document.write( "

Algebra.Com's Answer #79930 by checkley71(8403) $\"\"$ $\"About$

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F(-1/3)=18X^2-12X-3
\n" ); document.write( "F(-1/3)=18(-1/3)^2-12*(-1/3)-3
\n" ); document.write( "F(-1/3)=18*1/9+4-3
\n" ); document.write( "F(-1/3)=2+4-3
\n" ); document.write( "F(-1/3)=3 ANSWER. \n" ); document.write( "

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