document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1173921>Question 1173921</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Determine the sum of the 15 terms of the arithmetic series where the 5th term is 4 and consecutive terms increase by 3. <BR>\n" );
document.write( "A) 195<BR>\n" );
document.write( "B) 285<BR>\n" );
document.write( "C) 182<BR>\n" );
document.write( "D) 169 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #799277 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=799277\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Note: Both formal algebraic solutions from other tutors are fine; but there is a faster path to the answer.<br><BR>\n" );
document.write( "The sum of 15 terms of an arithmetic series is 15 times the middle term.<br><BR>\n" );
document.write( "In a series with 15 terms, the middle term is the 8th term.<br><BR>\n" );
document.write( "With 5th term 4 and common difference 3, the 8th term is 4+3(3) = 4+9 = 13.<br><BR>\n" );
document.write( "ANSWER: The sum is 15(13) = 195.<br><BR>\n" );
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