document.write( "Question 1173907: Given these key features:
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document.write( "f(0) = 5
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document.write( "leading coefficient is -2
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document.write( "zeroes at -3, -1, 4
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document.write( "Create two possible algebraic models, using two different degrees of polynomial functions.
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document.write( "Express both in standard and factored form. \n" );
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Algebra.Com's Answer #799275 by greenestamps(13216) You can put this solution on YOUR website! \n" ); document.write( "I would be curious to know if the requirements as you show them are really what was intended. It makes for strange polynomials. \n" ); document.write( "And if -3, -1, and 4 are to be the ONLY zeros, then there are no polynomials that satisfy all the conditions. \n" ); document.write( "The solutions are going to be complicated even in factored form; if you really need them in standard form, I'll let you do that part. \n" ); document.write( "Let's start with leading coefficient 2 and zeros at -3, -1, and 4. The basic polynomial is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "For that polynomial, f(0)=24; but the requirement is f(0)=5. \n" ); document.write( "To get a polynomial with the given zeros and leading coefficient, and also with f(0)=5, we need to add further linear factors of the form (x+a), (x+b), ..., where the product of ab... is 5/24. \n" ); document.write( "That will make f(0)=(5/24)(24)=5, as required; but of course it will add more zeros to the function. \n" ); document.write( "We can do it with one more factor of (x+5/24): \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Or we could do it with two additional linear factors, like (x+5/8) and (x+1/3): \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "I suspect, however, that it was not intended for you to do that kind of thing to answer the question. I think the statement of the problem simply put too many requirements on the function to make an answer possible. \n" ); document.write( " \n" ); document.write( " |