document.write( "Question 1173903: 2m + n = 0
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document.write( "m + 2n = 3 \n" );
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Algebra.Com's Answer #799217 by mahikab(11)![]() ![]() ![]() You can put this solution on YOUR website! There are several ways you can solve this problem if you're trying to solve for m and n. You can substitute, or systems of equations. However, I'm going to use substitution: \n" ); document.write( "2m + n = 0 => n = -2m \n" ); document.write( "We can input that in for the other equation: \n" ); document.write( "m + 2n = 3 now becomes: m + 2(-2m) = 3 \n" ); document.write( "Now we can solve: \n" ); document.write( "m + 2(−2m) = 3 \n" ); document.write( "m + −4m = 3 \n" ); document.write( "(m + −4m) = 3 (Combine Like Terms) \n" ); document.write( "−3m=3 \n" ); document.write( "m = -1 \n" ); document.write( "Now we can input that value in to solve for n: \n" ); document.write( "We said that n = -2m, and m = -1, so n = -2(-1): \n" ); document.write( "n = 2 \n" ); document.write( "Your final answer is m = -1, and n = 2, which can also be written as (m,n) = (-1,2) \n" ); document.write( "---------------------- \n" ); document.write( "However, if you were solving for m+n: \n" ); document.write( "You would add the two equations!: \n" ); document.write( "2m + n = 0 \n" ); document.write( "m + 2n = 3 \n" ); document.write( "---------- \n" ); document.write( "3m + 3n = 3 \n" ); document.write( "Now, you can take 3 common: \n" ); document.write( "3(m+n) = 3 \n" ); document.write( "m + n = 1 \n" ); document.write( "Your final answer for what m + n equals 1! \n" ); document.write( " |