document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1173877>Question 1173877</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A snack food is made by mixing 4 lb of popcorn that costs $0.80 per pound with caramel that costs $2.90 per pound. how much caramel is needed to make a mixture that costs $1.70 per pound? </SPAN>\n" );
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document.write( "Here is a non-algebraic method for solving this kind of two-part mixture problems that, with a little practice, can get you to the answer much faster and with less effort than setting up and solving an algebraic equation.<br><BR>\n" );
document.write( "Look at the three prices per pound of the two ingredients and the mixture on a number line: 0.80, 1.70, and 2.90.<BR>\n" );
document.write( "Determine by simple calculations that 1.70 is 0.90/2.10 = 3/7 of the way from 0.80 to 2.90.<BR>\n" );
document.write( "That means 3/7 of the mixture is the $2.90 per pound caramels, so 4/7 is the $0.80 per pound popcorn.<BR>\n" );
document.write( "And since the 4/7 of the mixture that is popcorn is 4 pounds, the 3/7 of the mixture that is caramels is 3 pounds.<br><BR>\n" );
document.write( "ANSWER: 3 pounds of caramels<br><BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "4(0.80)+3(2.90) = 3.20+8.70 = 11.90<BR>\n" );
document.write( "7(1.70) = 11.90<br><BR>\n" );
document.write( " </SPAN>\n" );
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