document.write( "Question 1173836: The president of a company traveled 1600 mi by jet and 300 mi on a prop plane. The rate of the jet was four times the rate of the prop plane. The entire trip took 10 h. Find the rate of the jet. \n" ); document.write( "
Algebra.Com's Answer #799160 by ikleyn(52803)\"\" \"About 
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document.write( "x = rate of the prop plane;\r\n" );
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document.write( "4x = rate of the jet.\r\n" );
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document.write( "The time equation is\r\n" );
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document.write( "    \"1600%2F%284x%29\" + \"300%2Fx\" = 10  hours.\r\n" );
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document.write( "Simplify\r\n" );
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document.write( "    \"400%2Fx\" + \"300%2Fx\" = 10\r\n" );
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document.write( "    \"700%2Fx\" = 10\r\n" );
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document.write( "       x   = \"700%2F10\" = 70 miles per hour  is the rate of the prop plane.\r\n" );
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document.write( "Hence, the rate of the jet is  4*70 = 280 mph.\r\n" );
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document.write( "CHECK.  \"1600%2F280\" + \"300%2F70\" = \"40%2F7\" + \"30%2F7\" = \"70%2F7\" = 10 hours.   ! Correct !\r\n" );
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