document.write( "Question 1173732: The sum of 8terms on AP is 160 while the sum of 20 terms is 880 find
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document.write( "The 43rd tert
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document.write( "The sum of 12 terms
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Algebra.Com's Answer #799051 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Sn=(n/2)(2a+(n-1)d) \n" ); document.write( "160=4(2a+7d) \n" ); document.write( "2a+7d=40 \n" ); document.write( "and \n" ); document.write( "880=10(2a+19d) \n" ); document.write( "2a+19d=88 \n" ); document.write( "12d=48 subtracting top from bottom \n" ); document.write( "d=4 \n" ); document.write( "that makes a=6 \n" ); document.write( "6/10/14/18/22/26/30/34=160 \n" ); document.write( "sun of 12 terms is \n" ); document.write( "S12+6(12+4(11))=336 \n" ); document.write( "160+38+42+46=50=336 \n" ); document.write( "- \n" ); document.write( "43rd term is a+(n-1)d=6+(42)*4 \n" ); document.write( "=174 \n" ); document.write( " \n" ); document.write( " |