document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=109617>Question 109617</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am have trouble solving this problem: solve for S 1/F= 1/S + 1/U  Would you please help me? I think the anwser is S=-1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #79902 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=79902\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> subtracting 1/U gives 1/F-1/U=1/S\r<BR>\n" );
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document.write( "finding a common denominator gives (U-F)/(FU)=1/S\r<BR>\n" );
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document.write( "taking the inverse gives (FU)/(U-F)=S </SPAN>\n" );
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