document.write( "Question 109618: How would I set this word problem up? The help would be greatly appreciated.
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Algebra.Com's Answer #79901 by ptaylor(2198) $\"\"$ $\"About$

You can put this solution on YOUR website!
Lets define a \"part\" here as a pint. (But we could just as easily define a \"part\" as a quart or a gallon or any liquid measure, for that matter).\r
\n" ); document.write( "\n" ); document.write( "6 gal=6*8=48 pints\r
\n" ); document.write( "\n" ); document.write( "Now we know that 50 pints is to 1 pint as 48 pints is to x. This is normally written as follows:\r
\n" ); document.write( "\n" ); document.write( "50/1=48/x multiply both sides by x (or cross-multiply)
\n" ); document.write( "50x=48 divide both sides by 50\r
\n" ); document.write( "\n" ); document.write( "x=0.96 pints\r
\n" ); document.write( "\n" ); document.write( "I would round it off to a pint!\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( "

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