document.write( "Question 1173712: A ferris wheel is 35 meters in diameter and boarded from a platform that is 2 meters above the ground. The six o'clock position on the ferris wheel is level with the loading platform. The wheel completes 1 full revolution in 6 minutes. The function h = f(t) gives your height in meters above the ground t minutes after the wheel begins to turn.\r
\n" ); document.write( "\n" ); document.write( "What is the Amplitude? ? meters
\n" ); document.write( "What is the Midline? y = ? meters
\n" ); document.write( "What is the Period? ? minutes
\n" ); document.write( "How High are you off of the ground after 3 minutes? ? meters
\n" ); document.write( "

Algebra.Com's Answer #799002 by htmentor(1343)\"\" \"About 
You can put this solution on YOUR website!
The general form for the height of the Ferris wheel as a function of time is:
\n" ); document.write( "h(t) = Acos(wt) + h0, where h0 is the midline, A is the amplitude, and w = the angular speed in radians per minute.
\n" ); document.write( "h(t) oscillates about the midline with an amplitude equal to the radius of the wheel.
\n" ); document.write( "The midline, i.e. halfway up, is given by the radius plus h0 = 19.5 m
\n" ); document.write( "Thus the amplitude is equal to 17.5 m. Since the initial height must be 2 m,
\n" ); document.write( "we have A = -17.5. The angular speed is 2*pi radians per 6 min = pi/3 rad/min.
\n" ); document.write( "Thus the equation describing the height is h(t) = -17.5*cos((pi/3)*t) + 19.5
\n" ); document.write( "The period, T is given by 2pi/w = 2pi/(pi/3) = 6 min.
\n" ); document.write( "h(3) = -17.5*cos(pi) + 19.5 = 17.5 + 19.5 = 37 m (maximum height)
\n" ); document.write( "A graph of the function is attached.
\n" ); document.write( "
\n" ); document.write( "
\n" );