document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1991>Question 1991</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A square plate of some size is cut at four corners. Equal squares of the same size are cut and is formed as open box.If this open box carries 128 ml of oil. What is the size of the side of the plate?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #799 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=799\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> classic question...\r<BR>\n" );
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document.write( "draw a diagram of a square, side x. In each corner draw a little square (the bit that will be cut out). Call its side length, y.\r<BR>\n" );
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document.write( "Once the sides are folded up to form the container, it will have a volume given by its base area*height\r<BR>\n" );
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document.write( "volume, V = (x-2y)(x-2y)(y)\r<BR>\n" );
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document.write( "so <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V+=+128+=+x%5E2y+-+4xy%5E2+%2B+4y%5E3 ALIGN=MIDDLE  ALT=\"V+=+128+=+x%5E2y+-+4xy%5E2+%2B+4y%5E3\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "You have 2 things you do not know but one equation...you cannot solve this.\r<BR>\n" );
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document.write( "You have to be given some other piece of information. Have a look at the question and see if you have missed anything out. Such as the size of y or the area of the original plate.\r<BR>\n" );
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document.write( "jon </SPAN>\n" );
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