document.write( "Question 1173675: A cabin cruiser leaves a harbour and travels south at 15km/h. One hour later a speed boat leaves the same harbour and travels on the same course at 25 km/h. How far from the harbour will the speed boat pass the cruiser? \n" ); document.write( "
Algebra.Com's Answer #798989 by greenestamps(13208)\"\" \"About 
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\n" ); document.write( "The cabin cruiser travels 15km in the 1 hour before the speedboat starts.

\n" ); document.write( "The rate at which the speedboat overtakes the cabin cruiser is the difference between their speeds, which is 25-15=10 km/h.

\n" ); document.write( "The time required to make up 15km at a rate of 10 km/h is 15/10 = 1.5 hours.

\n" ); document.write( "In 1.5 hours the speedboat will travel 25*1.5 = 37.5km.

\n" ); document.write( "ANSWER: The speedboat will overtake the cabin cruiser 37.5 km from the harbor.

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